2t^2-2t-12/4t^2-16+12

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Solution for 2t^2-2t-12/4t^2-16+12 equation: 


t in (-oo:+oo)

2*t^2-((12/4)*t^2)-(2*t)-16+12 = 0

2*t^2-3*t^2-2*t-16+12 = 0

-t^2-2*t-4 = 0

DELTA = (-2)^2-(-4*(-1)*4)

DELTA = -12

DELTA < 0

t belongs to the empty set

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